English, asked by hmadhu124, 1 year ago

biographical sketch of p.v Sindhu

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Answered by NaVila11
12
Heyy
Here is ur answer:-
Birth name-Pusarla Venkata Sindhu
Country-India
Born-5 July 1995 (age 22)
Hyderabad, Telangana, India[1]
Residence-Hyderabad, Telangana, India[2]
Height-5 ft 11 in (180 cm)
Weight-65 kg (143 lb)
Years active-2009–present
Handedness-Right
Coach-Pullela Gopichand
Mulyo Handoyo

Women's Singles
Highest ranking-2 (4 18.02.2018)
Current ranking-6 (07 December 2017)
may it helps :)
Answered by sourasghotekar123
1

Answer:

Biographical sketch of P.V Sindhu

Explanation:

  • P.V. Sindhu ( Pusarla Venkata Sindhu) is an Indian badminton player.
  • P. V. Sindhu was born on July 5, 1995. She is considered as one of the India's most successful player.
  • Sindhu has won many medals for the nation in various tournaments such as the Olympics and on the BWF circuit.
  • She is first and only Indian to become the badminton world champion and only the second individual athlete from India to win two consecutive medals at the Olympic Games.
  • She was born in Hyderabad, Andra Pradesh, India.
  • Her height is 1.79m, her weight is 65 kg.
  • Sindhu broke into the top 20 of the BWF World Rankings in September 2012, at the age of 17. She has won total 5 medals at the BWF World Championships.
  • Sindhu won her first super series title at the 2016 China Open and followed it up with four more finals in 2017.
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