Math, asked by arjunahirwar7081, 1 year ago

Biscuit Choco Pie 7/8 of the volume of their packets the remaining 1
/8 is unused it is decided to redesign the packet so that the amount of the unused space is reduced by 40% what fraction of the pack with the biscuit now take up

Answers

Answered by Louli
22

Answer:

The fraction of the new pack with biscuit is 0.925 which is equivalent to \frac{37}{40}

Explanation:

We are given that the unused fraction of the pack is \frac{1}{8}

In the redesign, the unused fraction is reduced by 40%

This means that:

new unused fraction = \frac{1}{8} - 0.4(\frac{1}{8} ) = \frac{1}{8} - \frac{1}{20} = \frac{3}{40} = 0.075

We know that the whole pack is equivalent to 100% which can be written as 1

Since 0.075 of the redesigned pack is empty, therefore:

new used fraction = 1 - 0.075 = 0.925 = \frac{37}{40}

Hope this helps :)

Answered by TooFree
26

Answer:

37/40


Step-by-step explanation:

Original Packaging

Used = 7/8 of the volume

Unused = 1/8 of the volume


Find the volume of unused space after the 40% reduce:

Volume Reduced = 40%

Volume Reduced = 0.4 x 1/8 = 1/20

Unused space = 1/8 - 1/20 = 3/40


Find the volume of the space used:

Volume of the space used = 1 - 3/40 = 37/40


Answer: 37/40

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