Bisector AD of angle BAC of triangle ABC passes through centre O of circumcircle of triangle.Prove that angle BOD = angle A
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Bisector AD of ∠BAC of ∆ABC passes through the centre of the circumcircle of ∆ABC as shown in the figure. Prove that AB = AC. Given: Bisector AD of ∠BAC of ∆ABC passes through the centre of the circumcircle of ∆ABC. ∴ AB = AC | C.P.C.T.
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