Question

Block of 8kg is lying on rough surface, with coefficient of friction 0.6 then limiting friction force is.

Answer 1

Answer

Limiting friction force = 48 N

Given

Block of 8 kg is lying on rough surface, with coefficient of friction 0.6

To Find

Limiting friction force

Formula Applied

$\rm F_{Lf}=\mu N\\\\\to\ \rm F_{Lf}=\mu mg\ \; \bigstar$

Solution

Mass , m = 8 kg

Coefficient of friction , μ = 0.6

Acceleration due to gravity , g = 10 m/s²

Apply formula ,

$\to\ \rm F_{Lf}=\mu mg\\\\\to\ \rm F_{Lf}=(0.6)(8)(10)\\\\\to\ \rm F_{Lf}=48\ N\ \; \bigstar$

Answer 2

Answer:

Limiting friction force = 48 N

Explanation: