Question

block of mass 10 kg slides on a horizontal road against friction with initial speed 216 km/h. If it stops

finally, then evaluate the work done by friction?​

Answer 1

Explanation:

$\mathfrak{\huge{\pink{\underline{\underline{\underline{\underline{Question-}}}}}}}$

block of mass 10 kg slides on a horizontal road against friction with initial speed 216 km/h. If it stops finally, then evaluate the work done by friction?

$\mathfrak{\huge{\pink{\underline{\underline{\underline{\underline{AnsWer}}}}}}}$

${\underline{\blue{\mathbf{Given \: Information, }}}}$

Mass of the Block (M) = 10Kg

Initial Velocity (u) = 216 Km/h = 216 × 5/18 = 12 × 5 = 60 m/s

Final Velocity (v) = 0 m/s

According to Work Energy Theorem,

Net work done by all forces is equal to the change in Kinetic Energy.

${\underline{\red{\mathbf{Now,}}}}$

Work Done = Change in KE

⟶ W = $\frac{1}{2}$Mv² - $\frac{1}{2}$Mu²

⟶ W = $\frac{1}{2}$(10)(0)² - $\frac{1}{2}$(10)(60)²

⟶ W = 0 - 5 × 3600

⟶ W = ${\underline{\blue{\mathbf{-18 \: KJ }}}}$

Work done by friction is ${\underline{\pink{\mathbf{-18 }}}}$

Answer 2

Answer:

-18 is the answer of question