Question

block of mass 2 kg tie

with a rope is going down under the force of gravity of 20 N as shown in the

diagram. How much force is required by the hand to stop the motion of the block?​

Answer 1

Answer:

Assuming the block was initially moving at a constant speed before the hand tried to stop it, the force required by the hand to stop the motion of the block would be equal in magnitude but opposite in direction to the force of gravity acting on the block.

The force of gravity acting on the block is given by:

F_gravity = m * g

where m is the mass of the block and g is the acceleration due to gravity (which is approximately 9.81 m/s^2).

Plugging in the values given in the problem, we get:

F_gravity = 2 kg * 9.81 m/s^2 = 19.62 N

Therefore, the force required by the hand to stop the motion of the block would be:

F_hand = -F_gravity = -19.62 N

Note that the negative sign indicates that the force exerted by the hand is in the opposite direction to the force of gravity.