bnt is a rhombus find x y z in the figure which will be given in the photo
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Let the intersection point of diagonals be o
We know that diagonals of Rhombus bisects each other at 90°
So,
TO = EO
y = 12
And,
BO = NO
z = 5
By applying Pythagoras theoram in triangle BOE
x^2 = 5^2 + 12^2
=> x^2 = 25 + 144
=> x^2 = 169
=> x = 13
We know that diagonals of Rhombus bisects each other at 90°
So,
TO = EO
y = 12
And,
BO = NO
z = 5
By applying Pythagoras theoram in triangle BOE
x^2 = 5^2 + 12^2
=> x^2 = 25 + 144
=> x^2 = 169
=> x = 13
ArchitectSethRollins:
what about x bro ? you didn't calculate the value of x .
Answered by
0
Hi friend
--------------
Your answer
--------------------
Given that : - BENT if a rhombus.
To find : - x , y and z.
Now,
------------
We know that, diagonals of a rhombus bisect each other.
So, y = 12 cm and z = 5 cm [Because the length of the diagonals is given.]
Then,
----------
By Pythagoras theorem ,
--------------------------------------
(5)² + (12)² = (x)²
=> 25 + 144 = x²
=> x² = 169
=> x = √169
=> x = 13 cm
Therefore,
-----------------
x = 13 cm
y = 12 cm
z = 5 cm
HOPE IT HELPS
--------------
Your answer
--------------------
Given that : - BENT if a rhombus.
To find : - x , y and z.
Now,
------------
We know that, diagonals of a rhombus bisect each other.
So, y = 12 cm and z = 5 cm [Because the length of the diagonals is given.]
Then,
----------
By Pythagoras theorem ,
--------------------------------------
(5)² + (12)² = (x)²
=> 25 + 144 = x²
=> x² = 169
=> x = √169
=> x = 13 cm
Therefore,
-----------------
x = 13 cm
y = 12 cm
z = 5 cm
HOPE IT HELPS
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