BO and CO are bisectors of angle b & angle c respectively of a angle ABC , intersecting each other at O. if angle BOC=100 DEGREE find angle BAC
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Answered by
12
In ΔABC, by angle sum property we have
2x + 2y + ∠A = 180°
⇒ x + y + (∠A/2) = 90°
⇒ x + y = 90° – (∠A/2) à (1)
In ΔBOC, we have
x + y + ∠BOC = 180°
90° – (∠A/2) + ∠BOC = 180° [From (1)]
∠BOC = 180° – 90° + (∠A/2)
∠BOC = 90° + (∠A/2)
2x + 2y + ∠A = 180°
⇒ x + y + (∠A/2) = 90°
⇒ x + y = 90° – (∠A/2) à (1)
In ΔBOC, we have
x + y + ∠BOC = 180°
90° – (∠A/2) + ∠BOC = 180° [From (1)]
∠BOC = 180° – 90° + (∠A/2)
∠BOC = 90° + (∠A/2)
Answered by
3
BOC=90 (angle a/2) hope you have received your ans
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