Math, asked by surbhi36, 1 year ago

bo anf co are external bisectors of angle b and angle c of triangle abc intersect at o if angle abc =70 digree find angle boc

Answers

Answered by girisai1967
29
PROOF

Angle A + Angle B + Angle C = 180°

So, Angle B + Angle C = 110° ( angle A = 70°)

Now, 1/2 (Angle B + Angle C) = 55°

1/2 angle B + 1/2 angle C =55°……….(1)

In triangle BOC

1/2 angle B + 1/2 angle C + Angle BOC = 180°

(BO and CO are angle bisectors)

Or, 55+ Angle BOC = 180° [Using (1)]

OR Angle BOC = 125°

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Answered by rohitkmrrk14
2

Answer:

Step-by-step explanation:

Angle A + Angle B + Angle C = 180°

So, Angle B + Angle C = 110° ( angle A = 70°)

Now, 1/2 (Angle B + Angle C) = 55°

1/2 angle B + 1/2 angle C =55°……….(1)

In triangle BOC

1/2 angle B + 1/2 angle C + Angle BOC = 180°

(BO and CO are angle bisectors)

Or, 55+ Angle BOC = 180° [Using (1)]

OR Angle BOC = 125°

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