bo anf co are external bisectors of angle b and angle c of triangle abc intersect at o if angle abc =70 digree find angle boc
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Answered by
29
PROOF
Angle A + Angle B + Angle C = 180°
So, Angle B + Angle C = 110° ( angle A = 70°)
Now, 1/2 (Angle B + Angle C) = 55°
1/2 angle B + 1/2 angle C =55°……….(1)
In triangle BOC
1/2 angle B + 1/2 angle C + Angle BOC = 180°
(BO and CO are angle bisectors)
Or, 55+ Angle BOC = 180° [Using (1)]
OR Angle BOC = 125°
Angle A + Angle B + Angle C = 180°
So, Angle B + Angle C = 110° ( angle A = 70°)
Now, 1/2 (Angle B + Angle C) = 55°
1/2 angle B + 1/2 angle C =55°……….(1)
In triangle BOC
1/2 angle B + 1/2 angle C + Angle BOC = 180°
(BO and CO are angle bisectors)
Or, 55+ Angle BOC = 180° [Using (1)]
OR Angle BOC = 125°
surbhi36:
thnkuu
Answered by
2
Answer:
Step-by-step explanation:
Angle A + Angle B + Angle C = 180°
So, Angle B + Angle C = 110° ( angle A = 70°)
Now, 1/2 (Angle B + Angle C) = 55°
1/2 angle B + 1/2 angle C =55°……….(1)
In triangle BOC
1/2 angle B + 1/2 angle C + Angle BOC = 180°
(BO and CO are angle bisectors)
Or, 55+ Angle BOC = 180° [Using (1)]
OR Angle BOC = 125°
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