boat is moving towards east with velocity 4m/s with respect to still water and river is flowing towards north with velocity 2m/s and the wind is blowing towards north with velocity 6m/s .The direction of the flag blown is..
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Velocity of boat=4m/s eastwards.
Velocity of river=2m/s northwards.
Velocity of wind=6m/s northwards.
Then, 8m/s northwards-2m/s eastward
6m/s notheast.
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Answer:
velocity of flag will be opposite to the velocity of boat and in the direction of flow of wind always..
now,velocity of boat is 4m/s in East and velocity of river 2m/s in North then River will drift the boat in the direction of its flow so Vnet of boat will be in b/w Vb and Vr..and as Vnet of boat changed direction of flow of flag will be opposite to vnet of boat I.e-4i -2j
now Vwind =6j and velocity of flag will be in the direction of wind then,
vnet= 6j-2j-4i =4j -4i
-4i+4j I.e South west
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