Bob has in his pocket a number of pennies, 5 times as many nickels as pennies and 5 more quarters than pennies. The coins amount to $2.27. Find the number of each kind of coin.
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Bob has in his pocket a number of pennies, 5 times as many nickels as pennies and 5 more quarters than pennies. If the coins amount to $3.29, how many of each kind of coin are in Bob’s pocket?
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In Bob’s pocket are 4 pennies, 20 nickels, and 9 quarters.
Algebraically, the formula would be as follows, with X representing 1 cent:
X + 25X [a nickel = 5X] + 25X [a quarter = 25X] + $1.25 [amt of 5 more quarters than pennies] = 3.29Subtract $1.25 from both sides and you end up with 51X = $2.04.Divide both sides by 51 and X =4Plug 4 into formula and you get4 pennies = $0.0420 (5 x 4) nickels = $1.004 + 5 = 9 quarters = $2.25Total = $3.29
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