Math, asked by Pandaaastha1617, 1 year ago

Bob packed 20 grapes and a pear in his lunch .he ate 13 grapes and a pear. what percent of the grapes did bob eat?

Answers

Answered by TooFree
17

Answer:

65% of the grapes


Step-by-step explanation:

Grapes packed = 20

Grapes eaten = 13

Percentage of grapes eaten = 13/20 x 100 = 65%


Answer: Bob ate 65% of the grapes

Answered by writersparadise
8

Answer:

Bob ate 65% of the grapes he had packed for lunch.

Step-by-step explanation:

Total grapes taken by Bob = 20

Total grapes Bob ate = 13

Therefore: Percentage of grapes eaten by Bob is 13 ÷ 20 X 100 = 65%

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