Question

BOC=90°+1/2of angle A​

Answer 1

Answer:

PLEASE WRITE FULL QUESTION LIKE WHATS GIVEN AND STUFF. ALSO IF THERE'S A FIGURE PLS ATTACH IT WITH THE Q

Step-by-step explanation:

Answer 2

Hey mate i don't know ur exact question becoz u have not completed ur question .But i guess ur question is this..........

1)Bisectors  of angles B and C of a triangle ABC intersect each other at the point O .prove <BOC= 90°+1/2 <A

In ΔABC, by angle sum property we have

2x + 2y + ∠A = 180°

⇒ x + y = 90° –  (∠A/2)  à (1)

⇒ x + y + (∠A/2) = 90°

In ΔBOC, we have

90° – (∠A/2) + ∠BOC = 180° [From (1)]

∠BOC = 90° + (∠A/2)

∠BOC = 180° – 90° + (∠A/2)

plz mark as brainlist ❤