Body has velocity of 5 m per second and uniform acceleration of 4 m per second square find the distance travelled in the 11th seconds of its motion
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Distance travelled by an object in nth second = s = u +1÷2a(2n-1)
s =5 +1÷2*4(2*11-1)
s =5 +2(22-1)
s =5+42
s=47 m
s =5 +1÷2*4(2*11-1)
s =5 +2(22-1)
s =5+42
s=47 m
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