body is projected upwards with a velocity u it passes through a certain point above the ground after given time t1 seconds. Time after which the body passes through the same point during the return journey is
Answers
Answered by
1
As the body is projected upwards we can write the equation as
h=ut-1/2gt2
gt2 -2ut +2h=0
t1+t2 are roots of equation
therefore t1+t2=[2u/g] ----->u=g/2(t1+t2)
therfore u=40 ms-1 or 40 m/sboth are same.
hop its helpful
h=ut-1/2gt2
gt2 -2ut +2h=0
t1+t2 are roots of equation
therefore t1+t2=[2u/g] ----->u=g/2(t1+t2)
therfore u=40 ms-1 or 40 m/sboth are same.
hop its helpful
Answered by
14
Hi mate
Refer the attachment
I Hope This Would Help You
Mark as Brainliest
Thank my answer and do follow..
Attachments:
Similar questions