Question

body moving with a uniform velocity of 10 ms power-1 comes to rest with an oceleration of 2ms power-2
Calculate the distance travelled by it before it comes to rest from a velocity of 10, ms power-1​

Answer 1

Answer:

Explanation:

initial velocity = 10m/s

final velocity = 0m/s    [ body came to rest ]

acceleration = 2m/s²

so, by third equation of motion

2 × acceleration× displacement = final velocity² - initial velocity²

2as = v² - u²

2×2[s] = 0² - 10²

4 [s] = -100

    s  = -100/4 = -25 m = 25m in negative direction