body of mass 1.5 kg thrown vertically upwards .Initial velocity is 15 meter per second . Wht will be the potential energy at end of 2 sec?
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Given, mass, m = 1.5 kg
Initial velocity, u = 15 m
Time, t = 2 s
From Newton’s second equation hf motion,
s = ut + 1/2 ${{gt}^{2}}$
=> s = 15 X 2 + — x10x 4 = 50 m
.’. Potential energy, PE = mgh
= 1.5x10x50 [-:h = s}
= 750J
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Initial velocity, u = 15 m
Time, t = 2 s
From Newton’s second equation hf motion,
s = ut + 1/2 ${{gt}^{2}}$
=> s = 15 X 2 + — x10x 4 = 50 m
.’. Potential energy, PE = mgh
= 1.5x10x50 [-:h = s}
= 750J
Mark as brainliest if it helped
Answered by
0
mass=1.5kg
u=15m/s
v=0
t=2s
as v=u+at
=0=15+a×2
-15/2=a
now,as h=s
v^2-u^2=2as
0-15×15=2×-15s/2
-15×15=-15s
15=s=h
now potential energy=mgh=15/10×9.8×15
220.5j=potential energy.
hope this helps! please mark me as brainliest!
u=15m/s
v=0
t=2s
as v=u+at
=0=15+a×2
-15/2=a
now,as h=s
v^2-u^2=2as
0-15×15=2×-15s/2
-15×15=-15s
15=s=h
now potential energy=mgh=15/10×9.8×15
220.5j=potential energy.
hope this helps! please mark me as brainliest!
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