Question

Body of mass 10 kg is acted upon a two perpendicular forces 1621 resultant acceleration of the body is

Answer 1

F=ma

a=F/m

=1621/18

a=162.1ms^-2

Answer 2

$f = ma \\ a = \frac{f}{m} \\ = \frac{1621}{18} \\ = 162.1 \:$

$= 162.1 \frac{m}{sec} {}^{2}$