Question

body of mass 2 kg is projected vertically upwards with a velocity 50 m/s from the ground. If g = 10 m/s2 then kinetic energy of the body at a height of 80 m from the ground​

Answer 1

Answer:

Applying energy conservation at time of projection, and returning at ground.

2

1

mu

2

=

2

1

mv

2

⟹u=v

It shows that particle is projected vertically upward with velocity of 2m/s then it returns with the same velocity.

So its kinetic energy=

2

1

mv

2

=

2

1

×2×(2)

2

=4J