body rises vertically upto a height of 125 m in 5 s & then comes back to the same point. Find the (i) total distance travelled, (ii) average speed, (iii) displacement and (iv) average velocity of the body.
Answers
Answer :
Maximum height attained = 125m
Time to reach there = 5s
Body comes back to the same point
We have to find
- Total distance travelled
- Average speed
- Displacement
- Average velocity
1) Distance is defined as the total length of actual path which is covered by moving object. It is a scalar quantity.
Here body rises to the height of 125m then comes back to the initial position.
Therefore distance covered by body will be two times of 125m.
➝ d = 125 × 2
➝ d = 250 m
2) Average speed is defined as the ratio of total distance travelled to the total time taken.
Here body takes 5s to reach at the maximum height. We know that time of ascent is always equal to the time of descent.
Therefore total time of flight will be 10s.
➝ Vav = d/t
➝ Vav = 250/10
➝ Vav = 25 m/s
3) Displacement is defined as the shortest distance between initial and final position of the entire journey.
ATQ, body comes back to the initial position therefore displacement will be zero.
4) Average velocity is defined as the ratio of displacement to the total time.
Displacement of the body is zero therefore average velocity will also be zero.
Explanation:
Given:
A body rises upto a height of 125 m in 5 seconds and come back to the same point.
To find:
- Total distance travelled
- Average speed
- Displacement .
- Average speed.
- Average velocity.
Solution:
1. As body rises upto a height of 125 m and comes back to the same point ,therefore total distance travelled will be
=2×125=250 m.
2.Average speed is total distance travelled /total time taken.
Total distance =250 m.
Total time taken=5×2=10 seconds.
Average speed:250/10=25 m/s.
3.Total displacement=0m ,as because reaches to the same point.
4.Average velocity=0 m/s,as because total displacement is 0.