Question

body starts falling from height h and travels distance h\2 during the last second of motion the time of travel in seconds is

Answer 1

time = theight = hh = 1/2 gt²2h = gt²
time to travel the first half = (t-1)so, h/2  = 1/2 g (t-1)²h = g (t-1)²
divide both equations2= t² / (t-1)²

taking under rot on both sidest/t-1 = √2 = 1.414t = 1.414 t - 1.414t = 3.41 s