Body travels 200 cm in the first 2 seconds and 220 cm in the next 4 seconds with retardation the velocity of the body at the end of 7th second is
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Answer:
v= 9.
Explanation:
200=2u+1/2a4
200= 2u+4a/2
- 200=2u+2a
- 420=6u+1/2a36
- 420=6u+18a
- 200=2u+2a×3
- {600=6a+6a} solve this two
- {420=6u+18a}
- 180=-12a
- a=-15
- a value sub in 200=2u+2a
- u=115 m/s
- v=u+at
- v=9
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