Question

Body travels for 15 sec starting from rest with constant acceleration. if it travels distances s1
.
s
2
and s3
in the first five seconds, second five seconds and next five seconds respectively, the
relation between s1
, s2
and s3
is.

Answer 1

Answer:

Let ‘v’ denotes speed and ‘a’ denotes acceleration.

At t=0, v0= 0

At t=5, v5= 5a

At t=10, v10= 10a

For interval-1, (t=0 to t=5)

S1=v0*5 + (1/2)*a*52= 12.5a

For interval-2, (t=5 to t=10)

S2= v5*5 + (1/2)*a*52= 37.5a

For interval-3, (t=10 to t=15)

S3= v10*5 + (1/2)*a*52= 62.5a

Therefore, S1: S2: S3= 1:3:5

thanks.