boiling point of water at 750 mm HG is 99.6 30 degree Celsius how much sucrose is to be added to 500 G of water such that it boils at hundred degree Celsius
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Answer: 124 g of sucrose is required.
Explanation:
ΔT=i x Kf x molality
ΔT=(100-99.63)°C =0.37°C=0.37K
Kf=0.512 for water
i=1, as sucrose does not ionize
Finding molality,
m=0.37/0.512=0.723
No of moles= molality x mass of solution
=0.723x500
=0.361 moles
Mass of sucrose required=No of moles x molecular mass of sucrose
=0.361 x 342
=124 g of sucrose
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