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The velocity of a body changes from 65 m/s - 98 m/s by Time of 12 s . What is distance covered by body if acceleration is 2.75 m/s2.
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Answer:
initial velocity =65m/
Final velocity= 98m/s
time =12s
acceleration =2.75m/s²
s = ut + 1 \2 at²
s represents distance covered
u represents initial velocity
t represents time
a represents acceleration
According to the formula:
s=(65×12)+{1/2×2.75×(12)²}
s=780+{1/2×2.75×144}
s=780+(2.75×72)
s=780+198
s=978 m
Therefore distance covered is 978m
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