Question

Bonjour ^-^


Write the configuration of Bromine according to aufbav rule .

State it's block , period no. , group no. and spin Multiciplity.

Is it paramagnetic or diamagnetic ?

Thanks ☺

Answer 1

Hey sis .....☺

Here's ur ans.⬇

Atomic no. of Bromine = 35

Therefore it's configuration = 1s^2 2s^2. 2p^6 3s^2. 3p^6. 4s^2. 3d^10. 4p^5

No. of unpaired electrons = 1

↪ Block = p
↪Period no. = 4
↪Group no. = (nse + npe)+ 10 = 17

↪Spin Multiciplity = 2|s| +1
= 2 × 1/2 + 1
= 2


It is paramagnetic as it has unpaired electrons .


Hope u understand ....

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Answer 2

hye,

Atomic number of bromine is 35

So its electronic configuration will be (Ar] 3d10 4s2 4p5

It lies in the 17th Group and in the P block and in 4th period.

It spin multiplicity is 2

It is paramagnetic and is unpaired