Boojho goes to the football ground to play football. The distance time graph of his journey from his home to the ground is given as figure. (a) What does the graph between point B and C indicate about the motion of Boojho? (b) Is the motion between 0 to 4 minutes uniform or nonuniform? (c) What is his speed between 8 and 12 minutes of his journey?
Answers
Given:
Boojho goes to the football ground to play football. The distance time graph of his journey from his home to the ground is given as figure.
To Find:
(a) What does the graph between point B and C indicate about the motion of Boojho? (b) Is the motion between 0 to 4 minutes uniform or nonuniform? (c) What is his speed between 8 and 12 minutes of his journey?
Answer:
(a) Boojho is at rest, i.e., his speed is zero because the graph is constant between point B and C.
(b) Non-uniform
(c) Speed = (225-150)/(12-8) = 75/4 =18.75
Answer:
a) Graph between point B and C is parallel to the x-axis as time is changing but distance remains the same means there is no motion.
Boojho is at rest position.
b) Motion between time 0 min to 4 min is nonuniform because the graph is not straight. It like two-line joining at point A.
c) At time 12-minute distance is 225 m and at time 8-minute distance is 150 m so speed is distance divided by the time taken
Speed =
= 18.75 m/min