Boran is unable to form BF6^3^- ion. Explain.
Attachments:
Answers
Answered by
12
Due to non-availability of d-orbitals , boran is unable to expand its octet .
Therefore , the maximum covalence of boran cannot exceed 4 .
Hence Boran cannot form BF6^3^- ion.
Answered by
5
Answer:
In boran there is no availability or d-orbital so it cannot form (BF6) ³ -ion.
If there is non-availability of d-orbital then it cannot form octet .
Similar questions