Boron exists as two stable isotopes; 10B(19%) and 11B(81%). Find out the average atomic weight of boron in the periodic table
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Answered by
2
Answer:
Average atomic weight =
100
∑%abundant×atomic mass
=
100
19×10+81×11
=10.81
Answered by
1
Explanation:
B -10. (19%) B-11. (81%)
Amu = m1p1+m2p2
=10*0.18+11*0.81
=1.9+8.91
=10.81
the answer is 10.8
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