Question

Boron has two isotopes b10 and b11 . The atomic mass of boron found to be10.72 the % of b10 in the mixture will be

Answer 1

Answer:

Explanation:

B10 and B11

Let B10 = x%

B11 = (100-x)%

Average atomic mass = 10x + 11(100-x)/100 = 10.80

10x + 11(100-x) = 1080

10x + 1100 - 11x = 1080

-x = - 20

x = 20

∴ B10 = 20% and B11 = (100-20)= 80%

Hope it will help you

Answer 2

B10 and B11

Let B10 = x%

B11 = (100-x)%

Average atomic mass = 10x + 11(100-x)/100 = 10.72

10x + 11(100-x) = 1072

10x + 1100 - 11x = 1072

-x = - 20

x = 20

∴ B10 = 20% and B11 = (100-20)= 80%