Math, asked by soumyajit29, 11 months ago

Bosco wishes to start a 200 m2 rectangular vegetable garden. Since he has only 50 m barbed wire, he fences three sides of the rectangular garden letting his house compound wall act as the fourth side of the fence. Find the dimensions of the garden.

Answers

Answered by rajsingh24
92

QUESTION :-

Bosco wishes to start a 200 m2 rectangular vegetable garden. Since he has only 50 m barbed wire, he fences three sides of the rectangular garden letting his house compound wall act as the fourth side of the fence. Find the dimensions of the garden.

ANSWER:-

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• DIMENSION TO RECTANGULAR VEGETABLE GARDEN,

LENGTH= L m.

BASE= B m.

Length of the barbed wire = 50m

According to the problem given,

=>l+b+l=50m.

=>.°.2l+b=50

=>.°.b=50-2l............(1)

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•AREA OF THE GARDEN:- 200m².

=>l b =200m²

=>l(50-2l)=200............(from 1)

=>.°.50L -l2²=200

Divide each term by 2, we get

25L- L²=100

=>.°.25L- L²+100=0

=>l²-20l -5l +100=0

=>l(l-20)-5(l-20)=0

=>.°.(l-20)=0 or (l-5)=0

=>.°. L =20 & L=5.

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Case 1:

If l = 20, then b = 50-2l

=> b = 50 - 40 = 10,

Case 2:

If l = 5 ,then b = 50-2l

=> b = 50 - 10 = 40,

Therefore,

Dimensions of the garden are (20,10) Or (5,40)

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Answered by Anonymous
26

☆Hey!

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