Both [Ni(CO)₄] and [Ni(CN)₄]²⁻ are diamagnetic. The
hybridisations of nickel in these complexes, respectively,
are
(a) sp³, sp³ (b) sp³, dsp²(c) dsp², sp³ (d) dsp², sp²
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Both [Ni(CO)₄] and [Ni(CN)₄]²⁻ are diamagnetic. The
hybridisations of nickel in these complexes, respectively,
are
(a) sp³, sp³
(b) sp³, dsp²
(c) dsp², sp³
(d) dsp², sp²
Answered by
0
The hybridization of nickel in these complexes, respectively, are sp3 and dsp2.
- Nickel is in (0) oxidation state in complex 1 and in (+2) oxidation state in complex 2.
- Nickel has a (d10) configuration in complex 1 and (d8) configuration in the second complex.
- CN- is a strong electron donor, so it enables pairing and therefore complex 2 has a dsp2 hybridization, while complex 1 has no empty d orbitals , so has to have a sp3 hybridization.
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