Question

The d electron configurations of Cr²⁺, Mn²⁺, Fe²⁺ and Ni²⁺
are 3d⁴, 3d⁵, 3d⁶ and 3d⁸ respectively. Which one of the
following aqua complexes will exhibit the minimum
paramagnetic behaviour?
(a) [Fe(H₂O)₆]²⁺ (b) [Ni(H₂O)₆]²⁺
(c) [Cr(H₂O)₆]²⁺ (d) [Mn(H₂O)₆]²⁺
(At. No. Cr = 24, Mn = 25, Fe = 26, Ni = 28)

Answer 1

Answer:

(b) [Ni(H₂O)₆]²⁺

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Answer 2

The aqua aqua complex that will exhibit the minimum  para-magnetic behaviour is  (b) [Ni(H₂O)₆]²⁺

As the number of unpaired electron increases, the magnetic moment also increases. Hence, as a result the para-magnetic behaviour also increases.

Therefore, the behaviour in following will be -

Cr²+(22) =3d`4 ( There are four unpaired electrons)

Mn²+(23) =3d`5 ( There are five unpaired electrons)

Fe²+(24) =3d`6 ( There are four unpaired electrons)

Ni²+(26) =3d`8 ( There are two unpaired electrons)

Thus,

[Ni(H₂O)₆]²⁺ exhibits the minimum para-magnetic behaviour.