Question

In which of the following complexes of the Co (at. no. 27),
will the magnitude of Do be the hightest?
(a) [Co(CN)₆]³⁻ (b) [Co(C₂O₄)₃]³⁻
(c) [Co(H₂O)₆]³⁺ (d) [Co(NH₃)₆]³⁺

Answer 1

Answer:

In which of the following complexes of the Co (at. no. 27),

will the magnitude of Do be the hightest?

(a) [Co(CN)₆]³⁻

(b) [Co(C₂O₄)₃]³⁻

(c) [Co(H₂O)₆]³⁺

(d) [Co(NH₃)₆]³⁺

Hope iT HelP YOu DEaR

Answer 2

[Co(CN)₆]³⁻ is the complex with magnitude of Δoct.

Explanation:

• Orbital splitting is the phenomenon which leads to the hybridization of the central atom varies and the different complexes are formed.

• Orbital splitting is directly dependent on the nature of that is forming the complex.

• The strong field  help to increase the orbital splitting energy and forms complexes with high number of .

• Where as, weak field  are those which cannot increase the magnitude of Δoct and thereby forms complexes with lesser number of .

• The overall strength of  vary as

           Iodide <bromide <chloride < fluoride <hydroxyl <water <ammonia <nitrite < cyanide

• So cyanide being a very strong field  helps to increase the magnitude of Δoct to maximum.

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