In which of the following complexes of the Co (at. no. 27),
will the magnitude of Do be the hightest?
(a) [Co(CN)₆]³⁻ (b) [Co(C₂O₄)₃]³⁻
(c) [Co(H₂O)₆]³⁺ (d) [Co(NH₃)₆]³⁺
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Answer:
In which of the following complexes of the Co (at. no. 27),
will the magnitude of Do be the hightest?
(a) [Co(CN)₆]³⁻
(b) [Co(C₂O₄)₃]³⁻
(c) [Co(H₂O)₆]³⁺
(d) [Co(NH₃)₆]³⁺
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[Co(CN)₆]³⁻ is the complex with magnitude of Δoct.
Explanation:
- Orbital splitting is the phenomenon which leads to the hybridization of the central atom varies and the different complexes are formed.
- Orbital splitting is directly dependent on the nature of that is forming the complex.
- The strong field help to increase the orbital splitting energy and forms complexes with high number of .
- Where as, weak field are those which cannot increase the magnitude of Δoct and thereby forms complexes with lesser number of .
- The overall strength of vary as
Iodide <bromide <chloride < fluoride <hydroxyl <water <ammonia <nitrite < cyanide
- So cyanide being a very strong field helps to increase the magnitude of Δoct to maximum.
For more information about orbital splitting energy,
https://brainly.in/question/2753424
Define crystal field splitting energy. - Brainly.in
https://brainly.in/question/6736255
Why crystal field splitting energy is less for tetrahedral and octahedral
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