Both player on 94 runs required runs only 7 for 3 balls how to hundred both playes
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{ If we don't consider a hint in the question, it will be impossible to get the answer. }
Consideration : Let us assume that wickets are left in hand.
Solution :
- In 1-st ball, the striker batsman will hit a 6 and individual hundred will be completed.
- In 2-nd ball, the striker will hit a ground shot but unfortunately will be run out while taking single and new batsman will come in the crease; non-striker batsman is in the striker's end now.
- In 3-rd ball, the striker will hit a 6 and individual hundred will be completed.
Thus the match will have score 6 + 6 = 12 and match can be won including centuries from both the batsmen on 94.
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