Question

Both points..

class 10th

trigonometry
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Answer 1

Given:-

Here, we have️

ABC a right angled triangle

Right - angled at B

AB = 24cm

BC = 7cm

To Find :-

(i)sin A , cos A

(ii) sin C , cos C

Solution :-

In ️ABC ,By Pythagoras theorem

AC² = AB² + BC²

AC² = 24² + 7²

AC² = 576 + 49

AC² = 625

AC=$\sqrt{625}$

Here, we have hypotenuse (AC) = 25

Therefore,

(i)

sin A = $\frac{p}{h} = \frac{7}{25}$

cos A = $\frac{b}{h} = \frac{24}{25}$

(ii)

sin C = $\frac{p}{h} = \frac{24}{25}$

cos C =$\frac{b}{h} = \frac{7}{25}$

And we are all done....!!

Answer 2

See this pic its also helps you dude