Question

Both ${[Co(NH3)6]}^{3+}$ and ${[CoF6]°{3-}$ are octahedral complexes. Predict the magnetic nature of the two complexes using CFT.

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Answer 1

$\huge\bf\mathscr\pink{your\: answer}$

step-by-step explanation:

${\bold{\green{\huge{Case\:(i)}}}}$

In ${[Co(NH3)6]}^{3+}$ ,

Co has oxidation state +3,

and its electronic configuration is 3${d}^{6}$ .

Since,

NH3 is a strong field ligand and ∆. > p ,

the pairing of electrons occur and electronic configuration is

t2g(6) eg(0).

Thus,

all electrons are paired and complex is

${\bold{\red{\huge{DIAMAGNETIC}}}}$

${\bold{\green{\huge{Case\:(ii)}}}}$

In ${[CoF6]}^{3-}$ ,

the oxidation state of Co is +3,

and electronic configuration is 3${d}^{6}$.

Hence,

∆. < p ,

so pairing up of electrons doesn't take place and electronic configuration is

t2g(4) eg(2).

Since,

there are 4 unpaired electrons,

the complex is

${\bold{\red{\huge{PARAMAGNETIC}}}}$