Question

Bowley's index number is 150. Fisher's index number is 149.95. Paasche's index number is

Answer 1

Answer:

$154.$

Step-by-step explanation:

Bowley's index number=$150$

Fisher's index number=$149.95$

Bowley index=$\frac{l+p}{2}$

Therefore,$l+p=150*2$

$l+p=300$                      [i]

Now,take the value of 'P' from the given question i.e,$(i)158  (ii)154  (iii)148  (iv)156$

Put these values in equation (i) one by one to get stastified value.

$l+158=300                             [p=158]\\l=142\\F.I=\sqrt{142*158}\\ F.I\neq 149.78$

If we put in equation (i) the value $p=154$

$l+154=300                        [p=154]\\l=146\\F.I=\sqrt{146*154}\\ F.I=149.95\\149.95=149.95$

Therefore,the paasche's index value is $154.$