Question

box is 0.56 M height 21 cm wide 44 cm long its volume is 51744 Cubic centimetre find the cost of painting its complete outer surface at the rate of 145 per cm2 ​

Answer 1

Step-by-step explanation:

FIRST TAKE OUT THE TOTAL SURFACE AREA OF CUBEOID (TSA) = 2[(LB) + (BH) + (HL)]

SO, IT WILL BE..

2 ×(21×44) + (21×0.56) + (0.56×44)

= 1884.4

TSA OF CUBEOID IS 1884.4.

PER CM SQUARE = 145

1884.4 CM SQUARE = 1884.4 × 145 = 2,73,238

FINAL ANSWER WILL BE = RUPEES 2,73,238

Answer 2

Answer:

The cost of painting the complete outer surface of the box is Rs. 1323560

Given,

Height of the box (h) = 0.56 m

= 56 cm

Width of the box (w) = 21 cm

Length of the box (l) = 44 cm

Volume of the box = 51744 cm^3

Cost to paint 1 cm^2 surface area of the box = Rs. 145

To find,

The cost of painting the complete outer surface of the box at Rs. 145 per cm^2

Solution

Surface area of the cuboid = 2×(l×w+w×h+h×l)

= 2×(44×21+21×56+56×44) cm^2

= 2×(924+1176+2464) cm^2

= 2×4564 cm^2

= 9128 cm^2

Since the cost of painting 1 cm^2 surface area of the box is Rs. 145

Therefore, the cost of painting 9128 cm^2 surface area of the box = Rs. 145 × 9128

= Rs. 1323560

Hence, the cost of painting the complete outer surface of the box is Rs. 1323560