boy opens a nut by applying a force of 100N using a wrench of length 20cm. If he wants to open it by a force of 20N what should be length of wrench?
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The torque is given as,
τ=F×l
By equating the torques on both sides, we get
F
1
×l
1
=F
2
×l
2
100×10=50×l
2
l
2
=20cm
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