boy playing runs from one end of a ground to the other end at a constant speed of 10 metre per minute and comes back the speed of V if the average speed of the total journey is 12 metre per minute then the value of B is
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15m/min
distance covered from one end to other is 'd' then for total is '2d'.
now time taken to go to other end is distance(d) /velocity(10m/min)
and time taken to return is distance(d)/velocity(v)
so now average velocity=total distance/total time taken.
now Vavg=2d/(d/10+d/v)
which is 12=2x10v/(10+v)
so 6=10v/(10+v)
finally we get 4v=60
therefore v=15m/min
Jayajevaa:
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