boy weighing 50kg finished long jump at a distance of 8 metre considering that he moved along a parabolic path and his angle of jump is angle of 45° his initial kinetic energy will be
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Answer:
Range = 8 m
or, (u^2)Sin(2×45°)÷2g = 8
or, u^2 = 8×2×10 m^2/s^2 = 160 m^2/s^2
Thus,
Initial K.E.
= m(u^2)/2
= 50×160÷2 = 4000 J (ANSWER)
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