bracket me a minus b minus C ka whole square find identity
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Answered by
37
(a-b-c)^2= a^2+b^2+c^2-2(ab-bc+ca)
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Hope it helps you and don't forget to mark me as the brainliest one !!!
Answered by
23
Hey user here is your answer.......
----> (a-b-c)^2=a^2+b^2+c^2-2(ab-bc+ca)
or
--> (a-b-c)^2=a2 + b2 + c2 – 2ab + 2bc – 2ca
Hope it helps you☺️
Regard
#Rohan ( Maths aryabhatta)
----> (a-b-c)^2=a^2+b^2+c^2-2(ab-bc+ca)
or
--> (a-b-c)^2=a2 + b2 + c2 – 2ab + 2bc – 2ca
Hope it helps you☺️
Regard
#Rohan ( Maths aryabhatta)
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