Question

bracket open a square B minus b c square bracket close whole square

Answer 1

Answer:

(a²b-bc²)²= b²(a+c)²(a-c)²= b²(a+c)²(a-c)²Or = b²(a+c)²(a-c)²Or = b²(a²+2ac+c²)(a²-2ac+c²)

Step-by-step explanation:

(a²b-bc²)²=[b(a²-c²)]²=[b(a+c)(a-c)]²

/* By algebraic identity:

x²-y² = (x+y)(x-y) */

= b²(a+c)²(a-c)²Or = b²(a²+2ac+c²)(a²-2ac+c²)

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