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HEYA USER !!
⤵HERE IS UR ANSWER --
GIVEN ::-
a = 3-√5/3+√5
now rationalize its denominator,,
= (3-√5/3+√5)*(3-√5/3-√5)
= (3-√5)^2 / (3)^2 - (√5)^2
= (3)^2 + (√5)^2 - 2*3*√5 / 9 - 5
= 9 + 5 - 6√5 / 4
= 14 - 6√5 / 4
= 2(7 - 3√5) / 4
= 7-3√5 / 2
b = 3+√5/3-√5
now rationalize its denominator,,
= (3+√5/3-√5)*(3+√5/3+√5)
= (3+√5)^2 / (3)^2 - (√5)^2
= (3)^2 + (√5)^2 + 2*3*√5 / 9 - 5
= 9 + 5 + 6√5 / 4
= 14 + 6√5 / 4
= 2(7 + 3√5) / 4
= 7+3√5 / 2
✔Now , a^2 - b^2 ,,
= (7-3√5/2)^2 - (7+3√5/2)^2
= 49+45-42√5 / 4 - (49+45+42√5 / 4)
= (49+45-42√5-49-45-42√5) / 4
= - 84√5 / 4
= - 21√5......
HOPE IT HELPS.....☺✌
⤵HERE IS UR ANSWER --
GIVEN ::-
a = 3-√5/3+√5
now rationalize its denominator,,
= (3-√5/3+√5)*(3-√5/3-√5)
= (3-√5)^2 / (3)^2 - (√5)^2
= (3)^2 + (√5)^2 - 2*3*√5 / 9 - 5
= 9 + 5 - 6√5 / 4
= 14 - 6√5 / 4
= 2(7 - 3√5) / 4
= 7-3√5 / 2
b = 3+√5/3-√5
now rationalize its denominator,,
= (3+√5/3-√5)*(3+√5/3+√5)
= (3+√5)^2 / (3)^2 - (√5)^2
= (3)^2 + (√5)^2 + 2*3*√5 / 9 - 5
= 9 + 5 + 6√5 / 4
= 14 + 6√5 / 4
= 2(7 + 3√5) / 4
= 7+3√5 / 2
✔Now , a^2 - b^2 ,,
= (7-3√5/2)^2 - (7+3√5/2)^2
= 49+45-42√5 / 4 - (49+45+42√5 / 4)
= (49+45-42√5-49-45-42√5) / 4
= - 84√5 / 4
= - 21√5......
HOPE IT HELPS.....☺✌
Answered by
2
Here is the solution.
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