Question

Brainlians !!

Find the distance up the plane upto which he can reach ? ​

Answer 1

Answer:

Given :

Ø = 60°

g = 10m/s²

Solution :

We know that,

Wnet = KEf - KEi

= - mgsinØ × s - f × s = 0 - 1/2 mu²

= - msinØ × s - u mg cosØ = -1/2 mu²

= 10×√3/2 × s + 0.1 × 10 ×1/2 × s = 1/2 × 10²

= 10 × 1.73 × s + 0.1 × 10 × s = 100

= 17.3 s × s = 100

= 18.3 = 100

s = 100/18.3

•°• s = 5.47

Answer 2

Given :

$\theta \: = \: 60°$

g = 10m/s²

Solution :

We know that,

Wnet = KEf - KEi

$= - mgsin \theta \: × \: s \: - \: f \: × \: s \: = \: 0 \: - \: 1/2 mu²$

$= - msin \theta \: × \: s \: - \: u mg cos \theta = -1/2 mu²$

= 10×√3/2 × s + 0.1 × 10 ×1/2 × s = 1/2 × 10²

= 10 × 1.73 × s + 0.1 × 10 × s = 100

= 17.3 s × s = 100

= 18.3 = 100

s = 100/18.3

$\therefore \: s \: = \: 5.47$