Math, asked by THEmultipleTHANKER, 1 month ago

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Find the perimeter of rectangle whose length and breadth are in the ratio 3 : 5and area is 1500 m²

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Answers

Answered by firdous41
2

Step-by-step explanation:

Perimeter of rectangle = 100m

ratio of length is to breadth = 3:2 = 3x : 2x

Perimeter = 2(l+b)

P = 2(3x+2x)

= 6x + 4x = 10x

10x = 100 ; x = 100/10 = 10

l = 3x = 3 × 10 = 30 m

b = 2x = 2 × 10 = 20 m

Area of rectangle = length × breadth ( l×b )

A = 30 × 20 = 600 sq.m

Answered by Anonymous
1

Answer:

Length of a rectangle field =3x

Breadth of a rectangle field =2x

Area =3456 m

2

3x×2x=3456 m

2

6x

2

=3456 m

2

x

2

=576 m

2

x=24 m

Therefore, the length =72 m

Breadth =48 m

Perimeter of the rectangular field =72+48=120 m

Cost of 1 meter =Rs.4

Cost of 120 meter =Rs.4×120=Rs.480.

Step-by-step explanation:

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