brainlies please answer
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in Δ ABC,
tan 30° = 3600√3 /CQ+QB
1/√3 = 3600√3/CQ+QB
CQ+QB = 3600*3
CQ+QB = 10800 ...(1)
IN Δ CQP,
TAN 60° =3600√3/CQ
√3=3600√3/CQ
CQ = 3600 ...(2)
FROM 1 AND 2
3600 + QB = 10800
QB = 7200m
ATQ, plane travel 7200m in 24sec
so, speed = 7200/24
= 300m/s or 1080km/h
tan 30° = 3600√3 /CQ+QB
1/√3 = 3600√3/CQ+QB
CQ+QB = 3600*3
CQ+QB = 10800 ...(1)
IN Δ CQP,
TAN 60° =3600√3/CQ
√3=3600√3/CQ
CQ = 3600 ...(2)
FROM 1 AND 2
3600 + QB = 10800
QB = 7200m
ATQ, plane travel 7200m in 24sec
so, speed = 7200/24
= 300m/s or 1080km/h
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