Question

BRAINLIEST QUESTION! !

(Provide me attachment)

Answer 1

Hey there!

Given,

Length of pendulum = 10 cm = 0.1 m

Let acceleration due to gravity be 10 m/s^2.

We know,

Time period = 2π√(l / g)

Time period = 2π√0.1 / 10)

Time period = 2π√1 / 100

Time period = 2π × 1 / 10

Time Period = π / 5 sec

Hence option (1) π / 5 sec  is correct..

Hope It Helps You!

Answer 2

Time period of a pendulum is the time taken to complete one oscillation or vibration . Now , the question is conceptual and we must know something other than the formula of time period .

First of all the time period of a simple pendulum does not depend on the amplitude for small angles . Here the angle is 3° and 6° which is very small compared to π or bigger angles .

So let us neglect the amplitude and we should also be aware of the fact that time period of pendulum does not depend on mass .

$\boxed{T=2\pi\sqrt{\dfrac{l}{g}}}$

What most of the students will do in this case is that they will take length in cm but it is absolutely wrong .

If the length is in cm and the value of g is in m/s² , then the equation will be wrong obviously as the dimensions won't match .

So length (l) = 10 cm ⇒ 10/100 m ⇒ 0.1 m .

Now assume g = 10 m/s² .

$T=2\pi\sqrt{\dfrac{l}{g}}\\\\\implies T=2\pi \sqrt{\dfrac{0.1}{10}}\\\\\implies T=2\pi \sqrt{\dfrac{1}{100}}\\\\\implies T=2\pi \times \dfrac{1}{10}\\\\\implies T=\dfrac{\pi}{5}sec$

Units will be in seconds as the value of m/s² in denominator gives s² and the metres get cancelled with length . So the square root of s² gives s .

Answer is OPTION (1) .

Thanks to @duragpalsingh for giving the question link .