Math, asked by Anonymous, 1 year ago

BRAINLIEST QUESTION!

Solve by factorization
4x² - 4a²x + (a^4 - b^4) = 0

Give answer with well explaining and step by step.​

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Answers

Answered by sujatakumari30071978
6

Answer:

4x²-4a²x+(a⁴-b⁴)=0

or, 4x²-2{(a²+b²)+(a²-b²)}x+(a²+b²)(a²-b²)=0

or, 4x²-2(a²+b²)x-2(a²-b²)x+(a²+b²)(a²-b²)=0

or, 2x{2x-(a²+b²)}-(a²-b²){2x-(a²+b²)}=0

or, {2x-(a²+b²)}{2x-(a²-b²)}=0

Either, 2x-(a²+b²)=0

or, 2x=a²+b²

or, x=(a²+b²)/2

Or, 2x-(a²-b²)=0

or, 2x=a²-b²

or, x=(a²-b²)/2

or, x=(a²+b²)/2,(a²-b²)/2. Ans.

Answered by amangoyal23
3

Answer:

BRAINLIEST QUESTION!

Solve by factorization

4x² - 4a²x + (a^4 - b^4) = 0

Give answer with well explaining and step by step.

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